What is the first derivative of-6x+1 ?

The first derivative of-6x+1 is -6

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derivative of-6x+1

\frac{d}{d x} (- 6 x + 1)

- 6

Solution steps

\frac{d}{d x} (- 6 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (6 x) + \frac{d}{d x} (1)

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (1) = 0

= - 6 + 0

Simplify

= - 6

\frac{\partial}{\partial x} (z sin (x y^{2} + 2 z))

\frac{\partial}{\partial x} (x y + z^{3} x - 2 yz)

\frac{\partial}{\partial x} (sin (x - y^{2}))

\int_{- 1}^{2} (x + 2 - x^{2})^{2} d x

t \to 1 lim (f (t))