What is the solution for y^{'''}-5y^{''}+3y^'+9y=0 ?

The solution for y^{'''}-5y^{''}+3y^'+9y=0 is y=c_{1}e^{-t}+c_{2}e^{3t}+c_{3}te^{3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}-5y^{''}+3y^'+9y=0

y^{^{'''}} - 5 y^{^{''}} + 3 y^{^{'}} + 9 y = 0

y = c_{1} e^{- t} + c_{2} e^{3 t} + c_{3} t e^{3 t}

Solution steps

y^{'''} (t) - 5 y^{''} (t) + 3 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{3 t} + c_{3} t e^{3 t}

y = c_{1} e^{- t} + c_{2} e^{3 t} + c_{3} t e^{3 t}

x \to - 10 lim (- 15)

\frac{d}{d x} (x, π x)

\frac{10}{1 + e ^{- x}}

\int \frac{1}{x ^{2} ( 2 x - 1 )} d x

\frac{d}{d x} (x^{3} + x - 1)

What is the solution for y^{'''}-5y^{''}+3y^'+9y=0 ?
The solution for y^{'''}-5y^{''}+3y^'+9y=0 is y=c_{1}e^{-t}+c_{2}e^{3t}+c_{3}te^{3t}