What is the derivative of x^3+x-1 ?

The derivative of x^3+x-1 is 3x^2+1

What is the first derivative of x^3+x-1 ?

The first derivative of x^3+x-1 is 3x^2+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{3} + x - 1)

3 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{3} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 3 x^{2} + 1 - 0

Simplify

= 3 x^{2} + 1

2 e^{(x - 5)}

\frac{x - 4}{x + 4}

\frac{d y}{d x} = 2 y

x \to 0 lim (sin (\frac{40 π}{x}))

\frac{1}{( s + 2 ) ^{4}}

What is the derivative of x^3+x-1 ?
The derivative of x^3+x-1 is 3x^2+1
What is the first derivative of x^3+x-1 ?
The first derivative of x^3+x-1 is 3x^2+1