What is the limit as x approaches 0 of sin((40pi)/x) ?

The limit as x approaches 0 of sin((40pi)/x) is diverges

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limit as x approaches 0 of sin((40pi)/x)

x \to 0 lim (sin (\frac{40 π}{x}))

diverges

Solution steps

x \to 0 lim (sin (\frac{40 π}{x}))

Apply Limit Divergence Criterion:

diverges

= diverges

\frac{1}{( s + 2 ) ^{4}}

(\frac{4 x ^{2}}{2 - x})^{3}

\int - 2 ln (x^{2} - 1) d x

f (x) = 11 x - 1

x \to 4 lim ((3 x - 3)^{\frac{5}{2}})

What is the limit as x approaches 0 of sin((40pi)/x) ?
The limit as x approaches 0 of sin((40pi)/x) is diverges