What is the solution for ds=2sqrt(s)dt ?

The solution for ds=2sqrt(s)dt is t=sqrt(s)+c_{1}

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ds=2sqrt(s)dt

d s = 2 s d t

t = s + c_{1}

Solution steps

d s = 2 s d t

Let

t

be the dependent variable. Divide by

d s

1 = 2 s \frac{d t}{d s}

Substitute

\frac{d t}{d s}

with

t^{'} (s)

1 = 2 s t^{^{'}} (s)

Isolate

t^{'} (s) : t^{'} (s) = \frac{1}{2 s}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

t = \int \frac{1}{2 s} d s

\int \frac{1}{2 s} d s = s + c_{1}

t = s + c_{1}

n = 0 \sum \infty 5 (- \frac{1}{3})^{n}

x \to 4 lim (\frac{( x ^{2} - 16 )}{2 - x})

\frac{d}{d x} (ln (2 e^{- x} sin (x)))

\int 1 + (tan (x))^{2} d x

g (x) = 6 - x

What is the solution for ds=2sqrt(s)dt ?
The solution for ds=2sqrt(s)dt is t=sqrt(s)+c_{1}