What is the limit as x approaches 0-of (x^2)/6-5/x ?

The limit as x approaches 0-of (x^2)/6-5/x is infinity

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limit as x approaches 0-of (x^2)/6-5/x

x \to 0 - lim (\frac{x ^{2}}{6} - \frac{5}{x})

\infty

Solution steps

x \to 0 - lim (\frac{x ^{2}}{6} - \frac{5}{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 - lim (\frac{x ^{2}}{6}) - x \to 0 - lim (\frac{5}{x})

x \to 0 - lim (\frac{x ^{2}}{6}) = 0

x \to 0 - lim (\frac{5}{x}) = - \infty

= 0 - (- \infty)

Simplify

0 - (- \infty) : \infty

= \infty

\frac{d}{d x} (\frac{1}{3} x^{3} - x)

x \to 0 lim (x^{3} - 4 x^{2})

\frac{\partial}{\partial z} (x z + e^{- x^{2} + y})

x \cdot (\frac{d y}{d x}) + y = 3

n = 1 \sum \infty 0. 5^{n}

What is the limit as x approaches 0-of (x^2)/6-5/x ?
The limit as x approaches 0-of (x^2)/6-5/x is infinity