What is the derivative of f(t)=(8t-7)^4+(8t+7)^4 ?

The derivative of f(t)=(8t-7)^4+(8t+7)^4 is 32768t^3+75264t

What is the first derivative of f(t)=(8t-7)^4+(8t+7)^4 ?

The first derivative of f(t)=(8t-7)^4+(8t+7)^4 is 32768t^3+75264t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (t) = (8 t - 7)^{4} + (8 t + 7)^{4}

32768 t^{3} + 75264 t

Solution steps

\frac{d}{d t} ((8 t - 7)^{4} + (8 t + 7)^{4})

Simplify

(8 t - 7)^{4} + (8 t + 7)^{4} : 8192 t^{4} + 37632 t^{2} + 4802

= \frac{d}{d t} (8192 t^{4} + 37632 t^{2} + 4802)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (8192 t^{4}) + \frac{d}{d t} (37632 t^{2}) + \frac{d}{d t} (4802)

\frac{d}{d t} (8192 t^{4}) = 32768 t^{3}

\frac{d}{d t} (37632 t^{2}) = 75264 t

\frac{d}{d t} (4802) = 0

= 32768 t^{3} + 75264 t + 0

Simplify

= 32768 t^{3} + 75264 t

\frac{\partial}{\partial x} (\frac{( 7 x + 7 y )}{z})

x \to 2 lim (\frac{5}{x ^{4} - 16})

t \to 0 lim ((\frac{3}{t 1 + t}) - \frac{3}{t})

\int 2 + 4 y^{2} d y

\frac{d}{d x} (x 49 - x^{2})

What is the derivative of f(t)=(8t-7)^4+(8t+7)^4 ?
The derivative of f(t)=(8t-7)^4+(8t+7)^4 is 32768t^3+75264t
What is the first derivative of f(t)=(8t-7)^4+(8t+7)^4 ?
The first derivative of f(t)=(8t-7)^4+(8t+7)^4 is 32768t^3+75264t