What is the derivative of f(0.6)=3arcsin(x^4) ?

The derivative of f(0.6)=3arcsin(x^4) is (12x^3)/(sqrt(1-x^8))

What is the first derivative of f(0.6)=3arcsin(x^4) ?

The first derivative of f(0.6)=3arcsin(x^4) is (12x^3)/(sqrt(1-x^8))

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derivative of

f (0.6) = 3 arcsin (x^{4})

\frac{12 x ^{3}}{1 - x ^{8}}

Solution steps

\frac{d}{d x} (3 arcsin (x^{4}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (arcsin (x^{4}))

Apply the chain rule:

\frac{1}{1 - ( x ^{4} ) ^{2}} \frac{d}{d x} (x^{4})

= \frac{1}{1 - ( x ^{4} ) ^{2}} \frac{d}{d x} (x^{4})

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 3 \cdot \frac{1}{1 - ( x ^{4} ) ^{2}} \cdot 4 x^{3}

Simplify

3 \cdot \frac{1}{1 - ( x ^{4} ) ^{2}} \cdot 4 x^{3} : \frac{12 x ^{3}}{1 - x ^{8}}

= \frac{12 x ^{3}}{1 - x ^{8}}

\int y e^{x^{2}} d x

\frac{\partial}{\partial x} (\frac{3 x ^{2}}{y - 5})

\frac{\partial}{\partial z} (\frac{x + y}{z})

ln (1 - e^{- x})

\frac{d}{d x} (4 x^{2} + 3 x - 7)

What is the derivative of f(0.6)=3arcsin(x^4) ?
The derivative of f(0.6)=3arcsin(x^4) is (12x^3)/(sqrt(1-x^8))
What is the first derivative of f(0.6)=3arcsin(x^4) ?
The first derivative of f(0.6)=3arcsin(x^4) is (12x^3)/(sqrt(1-x^8))