What is the solution for 3x-6ysqrt(x^2+1)((dy)/(dx))=0,y(0)=3 ?

The solution for 3x-6ysqrt(x^2+1)((dy)/(dx))=0,y(0)=3 is y=sqrt(\sqrt{x^2+1)+8}

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3x-6ysqrt(x^2+1)((dy)/(dx))=0,y(0)=3

3 x - 6 y x^{2} + 1 (\frac{d y}{d x}) = 0, y (0) = 3

y = x^{2} + 1 + 8

Solution steps

3 x - 6 y x^{2} + 1 (\frac{d y}{d x}) = 0

Solve separable ODE:

y = x^{2} + 1 + 8

y = x^{2} + 1 + 8

x^{\frac{12}{7}}

(\frac{x}{7} + 1)^{\frac{3}{2}}

\int_{1}^{3} x^{2} + \frac{1}{4 x ^{2}} d x

3 x + π^{2}

y = 4 x, x = 5, y = \frac{4}{x}

What is the solution for 3x-6ysqrt(x^2+1)((dy)/(dx))=0,y(0)=3 ?
The solution for 3x-6ysqrt(x^2+1)((dy)/(dx))=0,y(0)=3 is y=sqrt(\sqrt{x^2+1)+8}