What is the derivative of (e^x-1^2) ?

The derivative of (e^x-1^2) is 2(e^x-1)e^x

What is the first derivative of (e^x-1^2) ?

The first derivative of (e^x-1^2) is 2(e^x-1)e^x

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\frac{d}{d x} ((e^{x} - 1)^{2})

2 (e^{x} - 1) e^{x}

Solution steps

\frac{d}{d x} ((e^{x} - 1)^{2})

Apply the chain rule:

2 (e^{x} - 1) \frac{d}{d x} (e^{x} - 1)

= 2 (e^{x} - 1) \frac{d}{d x} (e^{x} - 1)

\frac{d}{d x} (e^{x} - 1) = e^{x}

= 2 (e^{x} - 1) e^{x}

\int \frac{( x + 3 )}{x ^{2} + 11 x + 18} d x

\frac{d}{d y} (y e^{2 x y} + x)

y = ln (4 x)

\int \frac{- 2}{x ^{2}} d x

\frac{d y}{d x} = \frac{x}{y ^{3}}

What is the derivative of (e^x-1^2) ?
The derivative of (e^x-1^2) is 2(e^x-1)e^x
What is the first derivative of (e^x-1^2) ?
The first derivative of (e^x-1^2) is 2(e^x-1)e^x