What is laplacetransform 5sin(3t) ?

The answer to laplacetransform 5sin(3t) is (15)/(s^2+9)

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laplacetransform 5sin(3t)

laplace transform

5 sin (3 t)

\frac{15}{s ^{2} + 9}

Solution steps

L {5 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= 5 \cdot \frac{3}{s ^{2} + 9}

Refine

5 \frac{3}{s ^{2} + 9} : \frac{15}{s ^{2} + 9}

= \frac{15}{s ^{2} + 9}

x \to \infty lim (\frac{9}{x} - 1)

f (x) = \frac{6 x ^{5} + 4 x}{x ^{4} + 3}

\int (2 x - 3) d x

\int cot^{5} (4 x) d x

\frac{1}{16 + x ^{2}}

What is laplacetransform 5sin(3t) ?
The answer to laplacetransform 5sin(3t) is (15)/(s^2+9)