What is the limit as x approaches 4+of-3/(8-2x) ?

The limit as x approaches 4+of-3/(8-2x) is infinity

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limit as x approaches 4+of-3/(8-2x)

x \to 4 + lim (- \frac{3}{8 - 2 x})

\infty

Solution steps

x \to 4 + lim (- \frac{3}{8 - 2 x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - 3 \cdot x \to 4 + lim (\frac{1}{8 - 2 x})

For

x

approaching

4

from the right

, x > 4 \Rightarrow 8 - 2 x < 0

The denominator is a negative quantity approaching 0 from the left

= - 3 (- \infty)

Apply Infinity Property:

- c \cdot (- \infty) = \infty

= \infty

x \to 0 lim (∣ x ∣ sin (x))

y = 5 tan (x), at x = \frac{π}{3}

\frac{d}{d x} (- \frac{1}{4 x})

ln (x - 1)

f (x) = ln (12 x)

What is the limit as x approaches 4+of-3/(8-2x) ?
The limit as x approaches 4+of-3/(8-2x) is infinity