What is the derivative of 4-2sin(2x-pi/4) ?

The derivative of 4-2sin(2x-pi/4) is -2sqrt(2)cos(2x)-2sqrt(2)sin(2x)

What is the first derivative of 4-2sin(2x-pi/4) ?

The first derivative of 4-2sin(2x-pi/4) is -2sqrt(2)cos(2x)-2sqrt(2)sin(2x)

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\frac{d}{d x} (4 - 2 sin (2 x - \frac{π}{4}))

- 22 cos (2 x) - 22 sin (2 x)

Solution steps

\frac{d}{d x} (4 - 2 sin (2 x - \frac{π}{4}))

Simplify

4 - 2 sin (2 x - \frac{π}{4}) : 4 - 2 sin (2 x) + 2 cos (2 x)

= \frac{d}{d x} (4 - 2 sin (2 x) + 2 cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) - \frac{d}{d x} (2 sin (2 x)) + \frac{d}{d x} (2 cos (2 x))

\frac{d}{d x} (4) = 0

\frac{d}{d x} (2 sin (2 x)) = 2 cos (2 x) \cdot 2

\frac{d}{d x} (2 cos (2 x)) = - 22 sin (2 x)

= 0 - 2 cos (2 x) \cdot 2 - 22 sin (2 x)

Simplify

= - 22 cos (2 x) - 22 sin (2 x)

\frac{\partial}{\partial x} (f (x) g (x))

\frac{\partial}{\partial y} (x^{\frac{1}{4}} y^{\frac{3}{4}})

\int_{- \infty}^{0} \frac{1}{4 - 8 x} d x

y^{^{'}} = \frac{x}{( 1 + 2 y )}, y (- 1) = 0

\frac{d}{d x} (cos (x) - 2 sin (x))

What is the derivative of 4-2sin(2x-pi/4) ?
The derivative of 4-2sin(2x-pi/4) is -2sqrt(2)cos(2x)-2sqrt(2)sin(2x)
What is the first derivative of 4-2sin(2x-pi/4) ?
The first derivative of 4-2sin(2x-pi/4) is -2sqrt(2)cos(2x)-2sqrt(2)sin(2x)