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Popular >

xy^'-4y=6x^4e^x

Solution

x y^{^{'}} - 4 y = 6 x^{4} e^{x}

Solution

y = 6 Ei (x) x^{4} + c_{1} x^{4}

Solution steps

x y^{'} (x) - 4 y = 6 x^{4} e^{x}

Solve linear ODE:

y = 6 Ei (x) x^{4} + c_{1} x^{4}

y = 6 Ei (x) x^{4} + c_{1} x^{4}

Popular Examples

tangent of f(x)=(-4x)/(x^2+1),\at x=-1 tangent of

f (x) = \frac{- 4 x}{x ^{2} + 1}, at x = - 1

integral from 0 to 1 of 2/(x^2+1)

\int_{0}^{1} \frac{2}{x ^{2} + 1} d x

d/(d{x)}({x}^4+{y}^4+{z}^4)

\frac{d}{d x} (x^{4} + y^{4} + z^{4})

derivative of sin(7x^2)

\frac{d}{d x} (sin (7 x^{2}))

x(dy)/(dx)=7xe^x-y+9x^2

x \frac{d y}{d x} = 7 x e^{x} - y + 9 x^{2}

Frequently Asked Questions (FAQ)

What is the solution for xy^'-4y=6x^4e^x ?
The solution for xy^'-4y=6x^4e^x is y=6\Ei(x)x^4+c_{1}x^4