What is the d/(d{x)}({x}^4+{y}^4+{z}^4) ?

The d/(d{x)}({x}^4+{y}^4+{z}^4) is 4{x}^3

What is the first d/(d{x)}({x}^4+{y}^4+{z}^4) ?

The first d/(d{x)}({x}^4+{y}^4+{z}^4) is 4{x}^3

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\frac{d}{d x} (x^{4} + y^{4} + z^{4})

4 x^{3}

Solution steps

\frac{d}{d x} (x^{4} + y^{4} + z^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (y^{4}) + \frac{d}{d x} (z^{4})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (y^{4}) = 0

\frac{d}{d x} (z^{4}) = 0

= 4 x^{3} + 0 + 0

Simplify

= 4 x^{3}

\frac{d}{d x} (sin (7 x^{2}))

x \frac{d y}{d x} = 7 x e^{x} - y + 9 x^{2}

x \to 1 lim (\frac{2}{x ^{2} - 7 x + 6})

f (x) = x^{3} cos (x)

\int e^{- r^{2}} \cdot r d r

What is the d/(d{x)}({x}^4+{y}^4+{z}^4) ?
The d/(d{x)}({x}^4+{y}^4+{z}^4) is 4{x}^3
What is the first d/(d{x)}({x}^4+{y}^4+{z}^4) ?
The first d/(d{x)}({x}^4+{y}^4+{z}^4) is 4{x}^3