What is the limit as x approaches 0 of 9/x-9/(x^2-x) ?

The limit as x approaches 0 of 9/x-9/(x^2-x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 9/x-9/(x^2-x)

x \to 0 lim (\frac{9}{x} - \frac{9}{x ^{2} - x})

diverges

Solution steps

x \to 0 lim (\frac{9}{x} - \frac{9}{x ^{2} - x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{9}{x} - \frac{9}{x ^{2} - x}) = \infty

x \to 0 - lim (\frac{9}{x} - \frac{9}{x ^{2} - x}) = - \infty

= diverges

ln (x) cos (x)

f (x) = (1 + 4 x)^{(\frac{3}{2})}, at x = 2

6 x^{2} - 4 x

\int \frac{1}{x ^{9}} d x

\frac{2}{( s ^{2} + 40 s + 400 )}

What is the limit as x approaches 0 of 9/x-9/(x^2-x) ?
The limit as x approaches 0 of 9/x-9/(x^2-x) is diverges