What is the tangent of 6x^2-4x ?

The tangent of 6x^2-4x is y=(12a_{0}-4)x-6a_{0}^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 6x^2-4x

tangent of

6 x^{2} - 4 x

y = (12 a_{0} - 4) x - 6 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0}^{2} - 4 a_{0})

Find the slope of

y = 6 x^{2} - 4 x : \frac{d y}{d x} = 12 x - 4

Compute the slope of

y = 6 x^{2} - 4 x

x = a_{0} : m = 12 a_{0} - 4

Find the line with slope m=

12 a_{0} - 4

and passing through

(a_{0}, 6 a_{0}^{2} - 4 a_{0}) : y = (12 a_{0} - 4) x - 6 a_{0}^{2}

y = (12 a_{0} - 4) x - 6 a_{0}^{2}

\int \frac{1}{x ^{9}} d x

\frac{2}{( s ^{2} + 40 s + 400 )}

2 x + 5, x^{2} + 2 x + 1, [- 2, 2]

\int 4 x^{\frac{1}{3}} + 2 x^{- \frac{2}{3}} + 9 d x

y = x^{2} - 6, y = 5 x

What is the tangent of 6x^2-4x ?
The tangent of 6x^2-4x is y=(12a_{0}-4)x-6a_{0}^2