What is the integral from 0 to 1 of 1/(x^{1/3)} ?

The integral from 0 to 1 of 1/(x^{1/3)} is 3/2

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integral from 0 to 1 of 1/(x^{1/3)}

\int_{0}^{1} \frac{1}{x ^{\frac{1}{3}}} d x

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\int_{0}^{1} \frac{1}{x ^{\frac{1}{3}}} d x

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{1}

= [\frac{3}{2} x^{\frac{2}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

2 x^{2}, 8 x - 2 x^{2}

(2 x - 1) d x + (5 y + 3) d y = 0

\int 1 + \frac{16}{x ^{\frac{2}{3}}} d x

\int_{4}^{2} x d x

\int \frac{- x}{e ^{x}} d x

What is the integral from 0 to 1 of 1/(x^{1/3)} ?
The integral from 0 to 1 of 1/(x^{1/3)} is 3/2