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Popular >

area 2x^2,8x-2x^2

Solution

area

2 x^{2}, 8 x - 2 x^{2}

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} 2 x^{2} - (8 x - 2 x^{2}) d x

Solve

\int_{0}^{2} 2 x^{2} - (8 x - 2 x^{2}) d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Popular Examples

(2x-1)dx+(5y+3)dy=0

(2 x - 1) d x + (5 y + 3) d y = 0

integral of sqrt(1+(16)/(x^{2/3))}

\int 1 + \frac{16}{x ^{\frac{2}{3}}} d x

integral from 4 to 2 of x

\int_{4}^{2} x d x

integral of (-x)/(e^x)

\int \frac{- x}{e ^{x}} d x

derivative of 900x-0.1x^2 derivative of

900 x - 0.1 x^{2}

Frequently Asked Questions (FAQ)

What is area 2x^2,8x-2x^2 ?
The answer to area 2x^2,8x-2x^2 is 16/3