What is the derivative of 2/(t^2) ?

The derivative of 2/(t^2) is -4/(t^3)

What is the first derivative of 2/(t^2) ?

The first derivative of 2/(t^2) is -4/(t^3)

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derivative of

\frac{2}{t ^{2}}

- \frac{4}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{2}{t ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 2 t^{- 2 - 1})

Simplify

2 (- 2 t^{- 2 - 1}) : - \frac{4}{t ^{3}}

= - \frac{4}{t ^{3}}

sin (x), cos (x), 0, \frac{π}{2}

(x - 1) y^{^{'}} - 2 + 3 x + y = 0

\int_{0}^{1} \frac{1}{e ^{x} + e ^{- x}} d x

\frac{d}{d x} (- 3 ln (3 + 4 x^{2}) + 5 x^{3} - 9)

y = 6

What is the derivative of 2/(t^2) ?
The derivative of 2/(t^2) is -4/(t^3)
What is the first derivative of 2/(t^2) ?
The first derivative of 2/(t^2) is -4/(t^3)