What is area sin(x),cos(x),0, pi/2 ?

The answer to area sin(x),cos(x),0, pi/2 is 2sqrt(2)-2

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area sin(x),cos(x),0, pi/2

area

sin (x), cos (x), 0, \frac{π}{2}

22 - 2

Decimal Notation

0.82842 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{2}} ∣ sin (x) - cos (x) ∣ d x

Solve

\int_{0}^{\frac{π}{2}} ∣ sin (x) - cos (x) ∣ d x : 22 - 2

The area is:

= 22 - 2

(x - 1) y^{^{'}} - 2 + 3 x + y = 0

\int_{0}^{1} \frac{1}{e ^{x} + e ^{- x}} d x

\frac{d}{d x} (- 3 ln (3 + 4 x^{2}) + 5 x^{3} - 9)

y = 6

t^{2} \frac{d y}{d t} - t = 1 + y + t y, y (1) = 10

What is area sin(x),cos(x),0, pi/2 ?
The answer to area sin(x),cos(x),0, pi/2 is 2sqrt(2)-2