What is the solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=10 ?

The solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=10 is y=11e^{-1/t+1}t-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^2(dy)/(dt)-t=1+y+ty,y(1)=10

t^{2} \frac{d y}{d t} - t = 1 + y + t y, y (1) = 10

y = 11 e^{- \frac{1}{t} + 1} t - 1

Solution steps

t^{2} \frac{d y}{d t} - t = 1 + y + t y

Solve separable ODE:

y = 11 e^{- \frac{1}{t} + 1} t - 1

y = 11 e^{- \frac{1}{t} + 1} t - 1

\frac{d}{d x} (6 x^{6})

\int_{- 35}^{0} \frac{1}{1 - x} d x

\int 2 x^{2} e^{x^{2}} d x

\int \frac{14}{x} d x

f (x) = x^{2} \cdot (x^{3} + 2)

What is the solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=10 ?
The solution for t^2(dy)/(dt)-t=1+y+ty,y(1)=10 is y=11e^{-1/t+1}t-1