What is the limit as x approaches 5 of (x^2+1)/(x-5) ?

The limit as x approaches 5 of (x^2+1)/(x-5) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of (x^2+1)/(x-5)

x \to 5 lim (\frac{x ^{2} + 1}{x - 5})

diverges

Solution steps

x \to 5 lim (\frac{x ^{2} + 1}{x - 5})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 5 + lim (\frac{x ^{2} + 1}{x - 5}) = \infty

x \to 5 - lim (\frac{x ^{2} + 1}{x - 5}) = - \infty

= diverges

\frac{1}{s ^{2} - 2 s + 3}

\frac{\partial}{\partial x} (3 x^{2} - 2 x + 6 y^{2} + 2 y + 2)

\int (u^{4} - u^{3} + u^{2}) d u

\frac{\partial}{\partial x} (4 y - 2 x y)

sin (2 x)

What is the limit as x approaches 5 of (x^2+1)/(x-5) ?
The limit as x approaches 5 of (x^2+1)/(x-5) is diverges