What is (\partial)/(\partial y)(x+y-8) ?

The answer to (\partial)/(\partial y)(x+y-8) is 1

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(\partial)/(\partial y)(x+y-8)

\frac{\partial}{\partial y} (x + y - 8)

1

Solution steps

\frac{\partial}{\partial y} (x + y - 8)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (8)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (8) = 0

= 0 + 1 - 0

Simplify

= 1

\frac{\partial}{\partial x} (e^{x^{2}} + 2 y^{3})

\int (x + 1) ln (x) d x

f (x) = x^{2} x^{3} + 1

\int x \cdot f (x) d x

What is (\partial)/(\partial y)(x+y-8) ?
The answer to (\partial)/(\partial y)(x+y-8) is 1