What is the derivative of \sqrt[3]{t}+2sqrt(t^3) ?

The derivative of \sqrt[3]{t}+2sqrt(t^3) is 1/(3t^{2/3)}+3sqrt(t)

What is the first derivative of \sqrt[3]{t}+2sqrt(t^3) ?

The first derivative of \sqrt[3]{t}+2sqrt(t^3) is 1/(3t^{2/3)}+3sqrt(t)

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derivative of

\frac{1}{3 t ^{\frac{2}{3}}} + 3 t

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (2 t^{3}) = 3 t

= \frac{1}{3 t ^{\frac{2}{3}}} + 3 t

\int \frac{2 x ^{2} + x + 2}{( x ^{2} + 1 ) ^{2}} d x

\frac{\partial}{\partial x} (\frac{2 \cdot x}{x ^{2} - y ^{2}})

\frac{d}{d z} (\frac{y}{z})

\frac{d}{d x} ((\frac{x + 1}{x - 1})^{3})

What is the derivative of \sqrt[3]{t}+2sqrt(t^3) ?
The derivative of \sqrt[3]{t}+2sqrt(t^3) is 1/(3t^{2/3)}+3sqrt(t)
What is the first derivative of \sqrt[3]{t}+2sqrt(t^3) ?
The first derivative of \sqrt[3]{t}+2sqrt(t^3) is 1/(3t^{2/3)}+3sqrt(t)