What is the first derivative of 4v^2-2 ?

The first derivative of 4v^2-2 is 8v

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derivative of 4v^2-2

derivative of

4 v^{2} - 2

8 v

Solution steps

\frac{d}{d v} (4 v^{2} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d v} (4 v^{2}) - \frac{d}{d v} (2)

\frac{d}{d v} (4 v^{2}) = 8 v

\frac{d}{d v} (2) = 0

= 8 v - 0

Simplify

= 8 v

x \to 0 lim (\frac{1}{x} sin (\frac{1}{x}))

\int 18 cos^{2} (x) sin (x) d x

x \to 0 lim (\frac{3 - 5 x}{4 x})

\int \frac{13}{x ^{2} + 1} d x

\frac{d y}{d x} = 3 y e^{x + 8}