What is the derivative of 5\sqrt[5]{x} ?

The derivative of 5\sqrt[5]{x} is 1/(x^{4/5)}

What is the first derivative of 5\sqrt[5]{x} ?

The first derivative of 5\sqrt[5]{x} is 1/(x^{4/5)}

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derivative of

\frac{1}{x ^{\frac{4}{5}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 5 \frac{d}{d x} (x^{\frac{1}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 5 \cdot \frac{1}{5} x^{\frac{1}{5} - 1}

Simplify

5 \cdot \frac{1}{5} x^{\frac{1}{5} - 1} : \frac{1}{x ^{\frac{4}{5}}}

= \frac{1}{x ^{\frac{4}{5}}}

\frac{1}{s - 5}

y^{^{'}} + 6 y = 60, y (1) = 110

y^{^{'}} = 19 x y

\frac{s ^{2}}{s ^{3} + 2 \cdot s ^{2} - 1}

\int_{0}^{7} \frac{6 t}{( t - 8 ) ^{2}} d t

What is the derivative of 5\sqrt[5]{x} ?
The derivative of 5\sqrt[5]{x} is 1/(x^{4/5)}
What is the first derivative of 5\sqrt[5]{x} ?
The first derivative of 5\sqrt[5]{x} is 1/(x^{4/5)}