What is (\partial)/(\partial x)(2xy-2x^2y) ?

The answer to (\partial)/(\partial x)(2xy-2x^2y) is 2y-4yx

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(\partial)/(\partial x)(2xy-2x^2y)

\frac{\partial}{\partial x} (2 x y - 2 x^{2} y)

2 y - 4 y x

Solution steps

\frac{\partial}{\partial x} (2 x y - 2 x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (2 x^{2} y)

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

= 2 y - 4 y x

x \to \infty lim (ln (5 x))

\int x x - 27 d x

\frac{d}{d x} (\frac{3}{x + 8})

\frac{3 x}{( x - 1 ) ^{4}}

\frac{d}{d x} (arctan (x^{2} + y^{2}))

What is (\partial)/(\partial x)(2xy-2x^2y) ?
The answer to (\partial)/(\partial x)(2xy-2x^2y) is 2y-4yx