What is the d/(dθ)(1-cos(θ)) ?

The d/(dθ)(1-cos(θ)) is sin(θ)

What is the first d/(dθ)(1-cos(θ)) ?

The first d/(dθ)(1-cos(θ)) is sin(θ)

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\frac{d}{d θ} (1 - cos (θ))

sin (θ)

Solution steps

\frac{d}{d θ} (1 - cos (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (1) - \frac{d}{d θ} (cos (θ))

\frac{d}{d θ} (1) = 0

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= 0 - (- sin (θ))

Simplify

= sin (θ)

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