What is the integral of-2.5-1/8 q ?

The integral of-2.5-1/8 q is -2.5q-0.0625q^2+C

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integral of-2.5-1/8 q

\int - 2.5 - \frac{1}{8} q d q

- 2.5 q - 0.0625 q^{2} + C

Solution steps

\int - 2.5 - \frac{1}{8} q d q

Simplify

= \int - 2.5 - 0.125 q d q

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2.5 d q - \int 0.125 q d q

\int 2.5 d q = 2.5 q

\int 0.125 q d q = 0.0625 q^{2}

= - 2.5 q - 0.0625 q^{2}

Add a constant to the solution

= - 2.5 q - 0.0625 q^{2} + C

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sin (3 x) + cos (8 x)

(1 + x^{2}) (\frac{d y}{d x}) - 2 x y = 0

\int_{\frac{π}{2}}^{π} x - sin (x) d x

What is the integral of-2.5-1/8 q ?
The integral of-2.5-1/8 q is -2.5q-0.0625q^2+C