What is (d^{10})/(dx^{10)}(cos(2x)) ?

The answer to (d^{10})/(dx^{10)}(cos(2x)) is -1024cos(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^{10})/(dx^{10)}(cos(2x))

\frac{d ^{10}}{d x ^{10}} (cos (2 x))

- 1024 cos (2 x)

Solution steps

\frac{d ^{10}}{d x ^{10}} (cos (2 x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= \frac{d ^{9}}{d x ^{9}} (- sin (2 x) \cdot 2)

\frac{d}{d x} (- sin (2 x) \cdot 2) = - 4 cos (2 x)

= \frac{d ^{8}}{d x ^{8}} (- 4 cos (2 x))

\frac{d}{d x} (- 4 cos (2 x)) = 8 sin (2 x)

= \frac{d ^{7}}{d x ^{7}} (8 sin (2 x))

\frac{d}{d x} (8 sin (2 x)) = 16 cos (2 x)

= \frac{d ^{6}}{d x ^{6}} (16 cos (2 x))

\frac{d}{d x} (16 cos (2 x)) = - 32 sin (2 x)

= \frac{d ^{5}}{d x ^{5}} (- 32 sin (2 x))

\frac{d}{d x} (- 32 sin (2 x)) = - 64 cos (2 x)

= \frac{d ^{4}}{d x ^{4}} (- 64 cos (2 x))

\frac{d}{d x} (- 64 cos (2 x)) = 128 sin (2 x)

= \frac{d ^{3}}{d x ^{3}} (128 sin (2 x))

\frac{d}{d x} (128 sin (2 x)) = 256 cos (2 x)

= \frac{d ^{2}}{d x ^{2}} (256 cos (2 x))

\frac{d}{d x} (256 cos (2 x)) = - 512 sin (2 x)

= \frac{d}{d x} (- 512 sin (2 x))

\frac{d}{d x} (- 512 sin (2 x)) = - 1024 cos (2 x)

= - 1024 cos (2 x)

t^{2} \cdot \frac{d x}{d t} = \frac{1}{x}

\frac{d}{d x} (8 x e^{4 x})

\int \frac{sin ^{2} ( x )}{x ^{2}} d x

f (x) = \frac{e ^{x}}{1 - e ^{x}}

15 y^{^{''}} - 7 y^{^{'}} - 4 y = 0

What is (d^{10})/(dx^{10)}(cos(2x)) ?
The answer to (d^{10})/(dx^{10)}(cos(2x)) is -1024cos(2x)