What is the derivative of (x^2-2^2) ?

The derivative of (x^2-2^2) is 4x(x^2-2)

What is the first derivative of (x^2-2^2) ?

The first derivative of (x^2-2^2) is 4x(x^2-2)

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\frac{d}{d x} ((x^{2} - 2)^{2})

4 x (x^{2} - 2)

Solution steps

\frac{d}{d x} ((x^{2} - 2)^{2})

Apply the chain rule:

2 (x^{2} - 2) \frac{d}{d x} (x^{2} - 2)

= 2 (x^{2} - 2) \frac{d}{d x} (x^{2} - 2)

\frac{d}{d x} (x^{2} - 2) = 2 x

= 2 (x^{2} - 2) \cdot 2 x

Simplify

= 4 x (x^{2} - 2)

\int_{1}^{3} \frac{6}{x} d x

f (x) = 4 x sin (x) cos (x)

(- 3, - 10), (4, 5)

y = 5 x^{4} f (x)

20 y^{^{''}} - y^{^{'}} + 7 y = 0

What is the derivative of (x^2-2^2) ?
The derivative of (x^2-2^2) is 4x(x^2-2)
What is the first derivative of (x^2-2^2) ?
The first derivative of (x^2-2^2) is 4x(x^2-2)