What is the first derivative of 2-x^2 ?

The first derivative of 2-x^2 is -2x

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derivative of 2-x^2

\frac{d}{d x} (2 - x^{2})

- 2 x

Solution steps

\frac{d}{d x} (2 - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

4 x (3 - 2 x)^{5}, at x = 2

\int \frac{x ^{2} - a ^{2}}{x ^{4}} d x

(2 x)^{^{'}}

\int \frac{( cos ^{3} ( x ) )}{3} d x

x \to 3 lim ((2 x^{2} - 4 x - 8)^{6})