What is area x=y^2-4y,x=-y^2+4y ?

The answer to area x=y^2-4y,x=-y^2+4y is No Solution

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area x=y^2-4y,x=-y^2+4y

area

x = y^{2} - 4 y, x = - y^{2} + 4 y

No Solution

Solution steps

Isolate

y

for

x = y^{2} - 4 y : y = 2 + x + 4, y = 2 - x + 4

Isolate

y

for

x = - y^{2} + 4 y : y = 2 - - x + 4, y = - x + 4 + 2

f_{1} (x) = 2 + x + 4

f_{2} (x) = 2 - x + 4

To find the intersection points solve

f_{i} (x) = f_{j} (x)

2 + x + 4 = 2 - x + 4 : x = - 4

2 + x + 4 = 2 - - x + 4 :

No Solution for

x \in R

2 + x + 4 = - x + 4 + 2 : x = 0

2 - x + 4 = 2 - - x + 4 : x = 0

2 - x + 4 = - x + 4 + 2 :

No Solution for

x \in R

2 - - x + 4 = - x + 4 + 2 : x = 4

Curves not bounded

= No Solution

y = x^{2} - x, (4, 12)

\int \frac{1}{x ^{2} ( x + 1 ) ^{3}} d x

f (x) = \frac{5 x}{x - 3}

n = 1 \sum \infty (2)^{n - 1}

\frac{1}{x ^{2} + 1} (\frac{d y}{d x}) = x e^{y}

What is area x=y^2-4y,x=-y^2+4y ?
The answer to area x=y^2-4y,x=-y^2+4y is No Solution