What is the solution for xy^'-y= 3/2 xln(x) ?

The solution for xy^'-y= 3/2 xln(x) is y= 3/4 ln^2(x)x+c_{1}x

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xy^'-y= 3/2 xln(x)

x y^{^{'}} - y = \frac{3}{2} x ln (x)

y = \frac{3}{4} ln^{2} (x) x + c_{1} x

Solution steps

x y^{'} (x) - y = \frac{3}{2} x ln (x)

Solve linear ODE:

y = \frac{3}{4} ln^{2} (x) x + c_{1} x

y = \frac{3}{4} ln^{2} (x) x + c_{1} x

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What is the solution for xy^'-y= 3/2 xln(x) ?
The solution for xy^'-y= 3/2 xln(x) is y= 3/4 ln^2(x)x+c_{1}x