What is the tangent of y=x^2+5x+2,(-5,2) ?

The tangent of y=x^2+5x+2,(-5,2) is y=-5x-23

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tangent of y=x^2+5x+2,(-5,2)

tangent of

y = x^{2} + 5 x + 2, (- 5, 2)

y = - 5 x - 23

Solution steps

Find the slope of

y = x^{2} + 5 x + 2 : \frac{d y}{d x} = 2 x + 5

Compute the slope of

y = x^{2} + 5 x + 2

(- 5, 2) : m = - 5

Find the line with slope m=

- 5

and passing through

(- 5, 2) : y = - 5 x - 23

y = - 5 x - 23

f (x) = - 3 - 6 x^{2}, (- 2, 27)

f (t) = t sin (t)

\frac{d}{d x} (tan (\frac{x ^{2}}{2 x + 3}))

\int - csc (x) d x

\frac{\partial}{\partial x} (ln (y) + 2 x y^{3})

What is the tangent of y=x^2+5x+2,(-5,2) ?
The tangent of y=x^2+5x+2,(-5,2) is y=-5x-23