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Popular >

y^'=e^{y+2x}

Solution

y^{^{'}} = e^{y + 2 x}

Solution

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

Solution steps

y^{'} (x) = e^{y + 2 x}

Solve separable ODE:

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

Popular Examples

integral from 0 to 1 of ((3t^2)/(1+t^3))

\int_{0}^{1} (\frac{3 t ^{2}}{1 + t ^{3}}) d t

integral of 1/(6+x)

\int \frac{1}{6 + x} d x

integral of sqrt(9+x^2)

\int 9 + x^{2} d x

(sec (x^{5} + x))^{^{'}}

integral of x/((x^2-x+1)(3x-2))

\int \frac{x}{( x ^{2} - x + 1 ) ( 3 x - 2 )} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{y+2x} ?
The solution for y^'=e^{y+2x} is y=-ln(-1/2 e^{2x}-c_{1})