What is the derivative of 2x^3-6x ?

The derivative of 2x^3-6x is 6x^2-6

What is the first derivative of 2x^3-6x ?

The first derivative of 2x^3-6x is 6x^2-6

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\frac{d}{d x} (2 x^{3} - 6 x)

6 x^{2} - 6

Solution steps

\frac{d}{d x} (2 x^{3} - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (6 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (6 x) = 6

= 6 x^{2} - 6

\int_{0}^{r} r^{2} - x^{2} d x

\frac{d}{d x} (3 x^{4} - 4 x^{3})

f (x) = \frac{3 x}{4} - 2

(2 - t) (4 + t^{2})^{- 1}

\frac{d}{d x} (- \frac{x ^{4}}{4} + x^{3} - x^{2})

What is the derivative of 2x^3-6x ?
The derivative of 2x^3-6x is 6x^2-6
What is the first derivative of 2x^3-6x ?
The first derivative of 2x^3-6x is 6x^2-6