What is (\partial)/(\partial z)(2y+z) ?

The answer to (\partial)/(\partial z)(2y+z) is 1

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(\partial)/(\partial z)(2y+z)

\frac{\partial}{\partial z} (2 y + z)

1

Solution steps

\frac{\partial}{\partial z} (2 y + z)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (2 y) + \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (2 y) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 + 1

Simplify

= 1

\int \frac{arcsin ( 5 x )}{1 - 25 x ^{2}} d x

t^{2} y^{^{''}} + 11 t y^{^{'}} + 25 y = 0

\frac{\partial}{\partial x} (e^{- 5 x^{2} - 2 y^{2}})

\int \frac{t ^{3} + 2}{t ^{4} + 8 t - 3} d t

x \to \infty - lim (e^{x})

What is (\partial)/(\partial z)(2y+z) ?
The answer to (\partial)/(\partial z)(2y+z) is 1