What is (\partial)/(\partial x)(e^{-5x^2-2y^2}) ?

The answer to (\partial)/(\partial x)(e^{-5x^2-2y^2}) is -10e^{-5x^2-2y^2}x

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(\partial)/(\partial x)(e^{-5x^2-2y^2})

\frac{\partial}{\partial x} (e^{- 5 x^{2} - 2 y^{2}})

- 10 e^{- 5 x^{2} - 2 y^{2}} x

Solution steps

\frac{\partial}{\partial x} (e^{- 5 x^{2} - 2 y^{2}})

Treat

y

as a constant

Apply the chain rule:

e^{- 5 x^{2} - 2 y^{2}} \frac{\partial}{\partial x} (- 5 x^{2} - 2 y^{2})

= e^{- 5 x^{2} - 2 y^{2}} \frac{\partial}{\partial x} (- 5 x^{2} - 2 y^{2})

\frac{\partial}{\partial x} (- 5 x^{2} - 2 y^{2}) = - 10 x

= e^{- 5 x^{2} - 2 y^{2}} (- 10 x)

Simplify

= - 10 e^{- 5 x^{2} - 2 y^{2}} x

\int \frac{t ^{3} + 2}{t ^{4} + 8 t - 3} d t

x \to \infty - lim (e^{x})

\int_{0}^{x} e^{x + y} d y

\frac{x + 1}{x + 2}

\frac{d}{d x} (- 64 sin (2 x))

What is (\partial)/(\partial x)(e^{-5x^2-2y^2}) ?
The answer to (\partial)/(\partial x)(e^{-5x^2-2y^2}) is -10e^{-5x^2-2y^2}x