What is the sum from n=2 to infinity of 2/(n^3) ?

The sum from n=2 to infinity of 2/(n^3) is converges

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sum from n=2 to infinity of 2/(n^3)

n = 2 \sum \infty \frac{2}{n ^{3}}

converges

Solution steps

n = 2 \sum \infty \frac{2}{n ^{3}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 2 \sum \infty \frac{1}{n ^{3}}

Apply p-Series Test:

converges

= 2 converges

= converges

n = 0 \sum \infty 2^{2 n}

\frac{d}{d x} (a^{f (x)})

\int e^{- θ} cos (2 θ) d θ

\int \frac{19 arctan ( x )}{x ^{2}} d x

x \to 0 lim (\frac{( x + 1 ) ^{3} - 1}{x})

What is the sum from n=2 to infinity of 2/(n^3) ?
The sum from n=2 to infinity of 2/(n^3) is converges