What is the integral from 1 to infinity of n/(n^2+1) ?

The integral from 1 to infinity of n/(n^2+1) is diverges

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integral from 1 to infinity of n/(n^2+1)

\int_{1}^{\infty} \frac{n}{n ^{2} + 1}

diverges

Solution steps

\int_{1}^{\infty} \frac{n}{n ^{2} + 1} d x

Compute the indefinite integral:

\int \frac{n}{n ^{2} + 1} d x = \frac{n}{n ^{2} + 1} x + C

Compute the boundaries:

\int_{1}^{\infty} \frac{n}{n ^{2} + 1} d x =

diverges

= diverges

x^{\frac{1}{2}}

x \to x lim (\frac{tan ( x )}{x})

x \to 1 lim (2 x^{3} - 4 x^{2} + x + 5)

\frac{d}{d x} (x + y \cdot ln (5 - \frac{x}{2}))

\frac{d}{d x} (4 x^{3} - 4 x)

What is the integral from 1 to infinity of n/(n^2+1) ?
The integral from 1 to infinity of n/(n^2+1) is diverges