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Popular >

derivative of f(x)=\sqrt[5]{x^4}-2/x

Solution

derivative of

Solution

\frac{4 x ^{3}}{5 ( x ^{4} ) ^{\frac{4}{5}}} + \frac{2}{x ^{2}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= \frac{4 x ^{3}}{5 ( x ^{4} ) ^{\frac{4}{5}}} - (- \frac{2}{x ^{2}})

Simplify

= \frac{4 x ^{3}}{5 ( x ^{4} ) ^{\frac{4}{5}}} + \frac{2}{x ^{2}}

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Frequently Asked Questions (FAQ)

What is the derivative of f(x)=\sqrt[5]{x^4}-2/x ?
The derivative of f(x)=\sqrt[5]{x^4}-2/x is (4x^3)/(5(x^4)^{4/5)}+2/(x^2)
What is the first derivative of f(x)=\sqrt[5]{x^4}-2/x ?
The first derivative of f(x)=\sqrt[5]{x^4}-2/x is (4x^3)/(5(x^4)^{4/5)}+2/(x^2)