What is the integral from-infinity to-1 of 1/(x^3) ?

The integral from-infinity to-1 of 1/(x^3) is -1/2

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integral from-infinity to-1 of 1/(x^3)

\int_{- \infty}^{- 1} \frac{1}{x ^{3}} d x

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

\int_{- \infty}^{- 1} \frac{1}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}} + C

Compute the boundaries:

\int_{- \infty}^{- 1} \frac{1}{x ^{3}} d x = - \frac{1}{2} - 0

= - \frac{1}{2} - 0

Simplify

= - \frac{1}{2}

\frac{d}{d x} (1 - 2 sin (x))

f (x) = 6 e^{x}

h \to + 6 lim (\frac{4 h}{h - 6})

f (x) = 9 - x

\int_{0}^{1} 3 e^{x^{2}} d x

What is the integral from-infinity to-1 of 1/(x^3) ?
The integral from-infinity to-1 of 1/(x^3) is -1/2