What is (\partial)/(\partial x)(t^8e^{-x}) ?

The answer to (\partial)/(\partial x)(t^8e^{-x}) is -e^{-x}t^8

Popular >

(\partial)/(\partial x)(t^8e^{-x})

\frac{\partial}{\partial x} (t^{8} e^{- x})

- e^{- x} t^{8}

Solution steps

\frac{\partial}{\partial x} (t^{8} e^{- x})

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= t^{8} \frac{\partial}{\partial x} (e^{- x})

Apply the chain rule:

e^{- x} \frac{\partial}{\partial x} (- x)

= e^{- x} \frac{\partial}{\partial x} (- x)

\frac{\partial}{\partial x} (- x) = - 1

= t^{8} e^{- x} (- 1)

Simplify

= - e^{- x} t^{8}

\frac{d}{d x} (\frac{x + 1}{x - 1})

\frac{\partial}{\partial x} (tan (5 + 2 x^{2} y^{3} z^{2}))

\frac{d}{d x} ((1 + sin (x)) \cdot cos (2 x))

\int \frac{2 x ^{2} + 3 x + 7}{x ^{3} + 3 x} d x

\frac{d y}{d x} = (cos (x)) e^{y + s i n (x)}, y (0) = 0

What is (\partial)/(\partial x)(t^8e^{-x}) ?
The answer to (\partial)/(\partial x)(t^8e^{-x}) is -e^{-x}t^8