What is the solution for (dy)/(dx)=(cos(x))e^{y+sin(x)},y(0)=0 ?

The solution for (dy)/(dx)=(cos(x))e^{y+sin(x)},y(0)=0 is y=-ln(-e^{sin(x)}+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(cos(x))e^{y+sin(x)},y(0)=0

\frac{d y}{d x} = (cos (x)) e^{y + s i n (x)}, y (0) = 0

y = - ln (- e^{s i n (x)} + 2)

Solution steps

\frac{d y}{d x} = (cos (x)) e^{y + s i n (x)}

Solve separable ODE:

y = - ln (- e^{s i n (x)} + 2)

y = - ln (- e^{s i n (x)} + 2)

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = - \frac{1}{5}, y^{^{'}} (0) = - \frac{8}{5}

3 e^{2 t} sin (4 t)

\frac{\partial}{\partial β} (sin (α) cos (β))

\frac{\partial}{\partial y} (x^{y^{z}})

\frac{d}{d x} (ln (\frac{2 x + 1}{x ^{2} - 2}))

What is the solution for (dy)/(dx)=(cos(x))e^{y+sin(x)},y(0)=0 ?
The solution for (dy)/(dx)=(cos(x))e^{y+sin(x)},y(0)=0 is y=-ln(-e^{sin(x)}+2)