What is (\partial)/(\partial y)(2x-2xy) ?

The answer to (\partial)/(\partial y)(2x-2xy) is -2x

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(\partial)/(\partial y)(2x-2xy)

\frac{\partial}{\partial y} (2 x - 2 x y)

- 2 x

Solution steps

\frac{\partial}{\partial y} (2 x - 2 x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (2 x y)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (2 x y) = 2 x

= 0 - 2 x

Simplify

= - 2 x

f^{^{'}} (x) = x^{\frac{1}{3}} (2 x - 1) (x + 1)

f (x) = 2 x + 1, at x = \frac{1}{4}

\int 4 e^{\frac{x}{2}} d x

\frac{d}{d x} ((2^{\frac{2}{3}} - x^{\frac{2}{3}})^{\frac{3}{2}})

\frac{d}{d x} (\frac{x ^{e^{x}}}{1 + x ^{2}})

What is (\partial)/(\partial y)(2x-2xy) ?
The answer to (\partial)/(\partial y)(2x-2xy) is -2x