What is the d/(dθ)(sin(θ)+cos(θ)) ?

The d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)

What is the first d/(dθ)(sin(θ)+cos(θ)) ?

The first d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)

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\frac{d}{d θ} (sin (θ) + cos (θ))

cos (θ) - sin (θ)

Solution steps

\frac{d}{d θ} (sin (θ) + cos (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (sin (θ)) + \frac{d}{d θ} (cos (θ))

\frac{d}{d θ} (sin (θ)) = cos (θ)

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= cos (θ) - sin (θ)

\int 8 x - 9 d x

\int (x + 4) cos (nπ x) d x

\int_{1}^{4} \frac{1}{w ^{2}} d w

\int (x + 2)^{2} (1 - x)^{6} d x

5 - x^{2}, sin (x), 0, 2

What is the d/(dθ)(sin(θ)+cos(θ)) ?
The d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)
What is the first d/(dθ)(sin(θ)+cos(θ)) ?
The first d/(dθ)(sin(θ)+cos(θ)) is cos(θ)-sin(θ)