What is the integral of cos^{16}(x)sin(x) ?

The integral of cos^{16}(x)sin(x) is -(cos^{17}(x))/(17)+C

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integral of cos^{16}(x)sin(x)

\int cos^{16} (x) sin (x) d x

- \frac{cos ^{17} ( x )}{17} + C

Solution steps

\int cos^{16} (x) sin (x) d x

Apply u-substitution

: \int - u^{16} d u

= \int - u^{16} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int u^{16} d u

Apply the Power Rule

: \frac{u ^{17}}{17}

= - \frac{u ^{17}}{17}

Substitute back

u = cos (x)

= - \frac{cos ^{17} ( x )}{17}

Add a constant to the solution

= - \frac{cos ^{17} ( x )}{17} + C

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What is the integral of cos^{16}(x)sin(x) ?
The integral of cos^{16}(x)sin(x) is -(cos^{17}(x))/(17)+C