What is (\partial)/(\partial x)(x^2-x-12y+1) ?

The answer to (\partial)/(\partial x)(x^2-x-12y+1) is 2x-1

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(\partial)/(\partial x)(x^2-x-12y+1)

\frac{\partial}{\partial x} (x^{2} - x - 12 y + 1)

2 x - 1

Solution steps

\frac{\partial}{\partial x} (x^{2} - x - 12 y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (12 y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (12 y) = 0

\frac{\partial}{\partial x} (1) = 0

= 2 x - 1 - 0 + 0

Simplify

= 2 x - 1

\frac{d}{d x} (524.8 \cdot x^{0.75})

\frac{d}{d x} (5 ln (2 x))

\int_{0}^{3 π} 7 x^{2} sin (\frac{1}{6} x) d x

y = \frac{x}{9} - \frac{9}{x}

\frac{d}{d x} (3 + 3 cos (x))

What is (\partial)/(\partial x)(x^2-x-12y+1) ?
The answer to (\partial)/(\partial x)(x^2-x-12y+1) is 2x-1